Total resistance increases, and ( I = V / R ), so current decreases.
In a series circuit, why does adding more resistors decrease current? dc circuit builder series circuit answer key
| Component | Measured Value | |-----------|----------------| | Battery voltage | 9.0 V | | Total current (ammeter anywhere) | 15 mA | | Voltage across R₁ | 1.5 V | | Voltage across R₂ | 3.0 V | | Voltage across R₃ | 4.5 V | Total resistance increases, and ( I = V
( R_T = 120\ \Omega ) ( I = 12 / 120 = 0.1\ \textA ) ( V_\texteach = 0.1 \times 40 = 4.0\ \textV ) Total resistance increases