Class 9 Higher Math Solution Bd File
Solution: Let opposite=3k, adjacent=4k Hypotenuse = √[(3k)² + (4k)²] = √(9k²+16k²) = 5k
Solution: AB = √[(4-1)² + (6-2)²] = √(9+16) = √25 = 5 BC = √[(7-4)² + (2-6)²] = √(9+16) = 5 CA = √[(1-7)² + (2-2)²] = √(36+0) = 6 Class 9 Higher Math Solution Bd
Solution: 3x - 7 > 2x + 5 → 3x - 2x > 5 + 7 → x > 12 Solution: Let opposite=3k
x₁ = (5+3)/4 = 8/4 = 2 x₂ = (5-3)/4 = 2/4 = 1/2 5 + 7 → x >